在该项目中，编写了MIPS Assembly程序以在给定环境中移动虚拟点机器人。
将提供环境的尺寸，机器人的起始坐标，障碍物的位置和移动命令。程序应根据给定的命令，环境尺寸和障碍物坐标移动机器人。在程序结束时，应显示机器人的最终坐标。
以下是输入示例：
3x5＃（1,2）＃（0,4），（2,3）＃ACCAGGGACEEEFFDB＃
3x5是所提供环境的尺寸。
（1,2）是机器人的初始坐标。
（0,4）和（2,3）是障碍物的坐标。
＃是分隔输入部分的字符。
虚拟演示示例环境
正如我们在环境的虚拟表示中看到的那样，显示了移动命令（A，B，C，D，E，F，G和H）的方向。
机器人的预期最终坐标为（2,2）。
当程序接收到移动命令时，它将检查下一个位置是否有障碍物。如果在下一个位置检测到障碍物，则程序应忽略移动命令。否则，程序将根据移动命令移动机器人。
以下是虚拟点机器人的MIPS汇编代码：
############################################ ####### A virtual point robot ############## ############################################ .data input: .space 201 # save the logic expression size_envir: .space 201 # save the dimensions of environment start_coordinate: .space 201 # save the start_coordinate of robot obstacles: .space 201 # save all coordinates of obstacles result: .asciiz "(" sign1: .asciiz "," sign2: .asciiz ")" .text #enables text input / output, kind of like String.h in C++ ######################################### ############### Main ################### ######################################### main: la $a0,input #input for logic expression to get dimensions of environment, starting coordinates... li $a1,201 li $v0,8 syscall # get the logic expression from the console la $a1,size_envir # save the dimensions of environment xori $s0,$a0,0x00 xori $s1,$a1,0x00 lb $t1, 0($s0) sb $t1,0($s1) lb $t1, 2($s0) sb $t1,1($s1) la $a1,start_coordinate # save the starting coordinates of robot xori $s0,$a0,0x00 xori $s1,$a1,0x00 lb $t1, 5($s0) sb $t1,0($s1) lb $t1, 7($s0) sb $t1,1($s1) lb $t6,0($s1) # save x-coordinate of robot lb $t7,1($s1) # save y-coordinate of robot la $a1,obstacles # save the coordinates of obstacles xori $s0,$a0,0x00 xori $s1,$a1,0x00 lb $t1, 11($s0) sb $t1,0($s1) lb $t1, 13($s0) sb $t1,1($s1) addi $a0,$a0,9 addi $a1,$a1,1 check_obstables: # check next obstacles addi $a0,$a0,6 xori $s0,$a0,0x00 lb $t1,0($s0) addi $t2,$zero,35 # detect the "#" character to know whether or not there is no next obstacles. addi $t3,$zero,44 # detect the "," character xori $t4,$s0,0x00 beq $t1,$t2,move_command # perform move commands beq $t1,$t3,next_obstacles # check next obstacles li $v0,10 # code for exit syscall # exit program ######################################################## next_obstacles: addi $t4,$t4,2 xori $s0,$t4,0 lb $t1,0($s0) addi $a1,$a1,1 xori $s1,$a1,0x00 sb $t1,0($s1) addi $a1,$a1,1 xori $s1,$a1,0x00 addi $s0,$s0,2 lb $t1,0($s0) sb $t1,0($s1) j check_obstables ###################################################### move_command: la $a3,obstacles subu $t5,$a1,$a3 #addi $t5,$t5,1 # $t5 is the number of obstacles ####################################################### move_doing: # do the move commands addi $a0,$a0,1 # next move command xori $s0,$a0,0x00 lb $t1,0($s0) addi $t2,$zero,35 beq $t1,$t2,finish # if the command is #, finish the program. otherwise, move on the command ##################################################### # Continue to do the command ##################################################### xori $t2,$zero,0x41 # "A" command beq $t1,$t2,A_command xori $t2,$zero,0x42 # "B" command beq $t1,$t2,B_command xori $t2,$zero,0x43 # "C" command beq $t1,$t2,C_command xori $t2,$zero,0x44 # "D" command beq $t1,$t2,D_command xori $t2,$zero,0x45 # "E" command beq $t1,$t2,E_command xori $t2,$zero,0x46 # "F" command beq $t1,$t2,F_command xori $t2,$zero,0x47 # "G" command beq $t1,$t2,G_command xori $t2,$zero,0x48 # "H" command beq $t1,$t2,H_command li $v0,10 # code for exit syscall # exit program A_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 addi $t2,$t2,1 addi $t4,$t5,0 j check_border B_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 addi $t2,$t2,1 addi $t1,$t1,1 addi $t4,$t5,0 j check_border C_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 addi $t1,$t1,0x01 addi $t4,$t5,0 j check_border D_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 addi $t1,$t1,0x01 xori $t3,$zero,0x01 sub $t2,$t2,$t3 addi $t4,$t5,0 j check_border E_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 xori $t3,$zero,0x01 sub $t2,$t2,$t3 addi $t4,$t5,0 j check_border F_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 xori $t3,$zero,0x01 sub $t2,$t2,$t3 sub $t1,$t1,$t3 addi $t4,$t5,0 j check_border G_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 xori $t3,$zero,0x01 sub $t1,$t1,$t3 addi $t4,$t5,0 j check_border H_command: xori $t1,$t6,0x00 xori $t2,$t7,0x00 xori $t3,$zero,0x01 sub $t1,$t1,$t3 addi $t2,$t2,1 addi $t4,$t5,0 j check_border check: #t4 is the number of obstacles #t1: x new #t2: y new la $a3,obstacles add $s0,$a3,$t4 lb $t3,0($s0) beq $t3,$t2,keep_1 xori $t3,$zero,0x01 sub $t4,$t4,$t3 j next_check keep_1: xori $t3,$zero,0x01 sub $t4,$t4,$t3 la $a3,obstacles add $s0,$a3,$t4 lb $t3,0($s0) beq $t3,$t1,keep_position j next_check next_check: xori $t3,$zero,0x01 sub $t4,$t4,$t3 bltz $t4,update_robot j check ######################################### check_border: xori $t3,$zero,48 blt $t1,$t3,keep_position xori $t3,$zero,48 blt $t2,$t3,keep_position la $a3, size_envir xori $s0,$a3,0x00 lb $t3,0($s0) beq $t1,$t3,keep_position xori $s0,$a3,0x00 lb $t3,1($s0) beq $t2,$t3,keep_position j check ######################################### update_robot: addi $t6,$t1,0 # x-coordinate addi $t7,$t2,0 # y-coordinate j move_doing ######################################### keep_position: j move_doing ######################################### finish: # finish all the command and output the final coordinate of robot li $v0, 4 # $system call code for print_str la $a0, result # $address of string to print syscall # print the string li $v0, 1 # $system call code for print_int xori $t1,$zero,48 subu $t6,$t6,$t1 xori $a0,$t6,0x00 # $integer to print syscall # print it li $v0, 4 # $system call code for print_str la $a0, sign1 # $address of string to print syscall li $v0, 1 # $system call code for print_int xori $t1,$zero,48 subu $t7,$t7,$t1 xori $a0,$t7,0x00 # $integer to print syscall li $v0, 4 # $system call code for print_str la $a0, sign2 # $address of string to print syscall li $v0,10 # code for exit syscall # exit program ##########################################
该程序在Qtspim上进行了验证，并获得了机器人的正确最终坐标，如下图所示。
程序结果
您可能会这样：
没意见：
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